Let the quantity of milk & water in first container be 3x & 4x respectively
& The quantity of milk & water in second container be 5y & 6y respectively
The quantity of milk in third container = 4/9×18=8 litres
The quantity of water in third container = 18 – 8 = 10 liters
ATQ,
3x+5y= 8 ………..(I)
4x+6y = 10 ………(II)
From (I)&(II)
x=1, y=1
Required quantity = 3x = 3 liters
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