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    A person mixed milk and water in two containers in the ratio 3 : 4 and 5 : 6 respectively then he mixed both the mixture in the third container and th
    Question



    A person mixed milk and water in two containers in the ratio 3 : 4 and 5 : 6 respectively then he mixed both the mixture in the third container and the ratio of milk and water in the resultant mixture becomes 4 : 5. Total quantity of mixtures is 18 liters. Find the quantity(in liters) of milk in the 1st container.

    A.

    1.5

    B.

    3

    C.

    6

    D.

    4.5

    E.

    2.1

    Correct option is B

    Let the quantity of milk & water in first container be 3x & 4x respectively
    & The quantity of milk & water in second container be 5y & 6y respectively
    The quantity of milk in third container = 4/9×18=8 litres
    The quantity of water in third container = 18 – 8 = 10 liters
    ATQ,
    3x+5y= 8 ………..(I)
    4x+6y = 10 ………(II)
    From (I)&(II)
    x=1, y=1
    Required quantity = 3x = 3 liters

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