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    A man sold an article for ₹390 by first giving a d% discount on its marked price, and then another discount having the same nominal value (in ₹). If t
    Question

    A man sold an article for ₹390 by first giving a d% discount on its marked price, and then another discount having the same nominal value (in ₹). If the marked price of the article is ₹3900, then what is the value of d?

    A.

    45

    B.

    50

    C.

    48

    D.

    41

    Correct option is A

     Given: 

    The marked price of the article is 3900.

    A man sold an article for 390

    First giving a d% discount on its marked price

    Formula used: 

    Discount=d100×100Discount = \frac{d}{100}\times 100 

    Solution: 

    First Discount=d100×3900=39dFirst \ Discount = \frac{d}{100}\times 3900 = 39d 

    After the first discount,

    Price after first Discount=M39d=390039d.\text{Price after first Discount} = M - 39d = 3900-39d.  

    After the second discount,

    Price after second Discount=(390039d)39d=390078d\text{Price after second Discount} = ( 3900- 39d) -39d = 3900- 78d 

    The final selling price is 390.

    390078d=390.3900- 78d = 390. 

    3900390=78d3900 - 390 = 78d 

    3510=78d3510 = 78d 

    d=351078=45d = \frac{3510}{78}= 45 

    Thus, the value of ddd is 45.  

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