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    A man increases his consumption of sugar by 44.44% because the price of sugar is reduced by P%. Find P. (Expenditure remains constant.)
    Question

    A man increases his consumption of sugar by 44.44% because the price of sugar is reduced by P%. Find P. (Expenditure remains constant.)

    A.

    301013%30\frac{10}{13}\%​​

    B.

    321013%32\frac{10}{13}\%​​

    C.

    201013%20\frac{10}{13}\%​​

    D.

    251013%25\frac{10}{13}\%​​

    Correct option is A

    Given:

    A man increases consumption by 44.44%

    Solution:

    Let the price of sugar be Rs.100

    And consumption be 100

    Total expenditure = 100×100100 \times 100​ = 10000

    Consumption increased by 44.44% = 49 \frac{4}{9}​​

    New consumption = 100 + 44.44% of 100 = 13009\frac{1300}{9}​​

    Let the dropped price be xx​​

    Then, expenditure = x×13009x \times \frac{1300}{9} 

    But the expenditure is same in both cases;

    Hence,

    x×13009=10000x \times \frac{1300}{9}= 10000​​

    x=10000×91300=90013x =\frac{10000\times 9}{1300}= \frac{900}{13}​​

    Price dropped = 10090013=130090013100- \frac{900}{13}= \frac{1300-900}{13}​​

    =40013=\frac{400}{13}​​

    Percentage dropped =40013100×100=40013%=301013% \frac{\frac{400}{13}}{100} \times 100 = \frac{400}{13}\% =30\frac{10}{13}\% 

    Alternate Method:

    Consumption increases by 44.44% (i.e. 49)\frac{4}{9})​.

    Expenditure is constant.

    With constant expenditure: (Price factor)×(Quantity factor)=\text{Price factor}) \times (\text{Quantity factor}) =​ 1.

    Price increase by P%.

    Price factor = 1P1001-\dfrac{P}{100}​; Quantity factor = 1+49=139+\dfrac{4}{9}=\dfrac{13}{9}​.

    (1P100)×(139)=1\left(1-\frac{P}{100}\right)\times\left(\frac{13}{9}\right)=1​​
    1P100=9131-\frac{P}{100}=\frac{9}{13}

    P100=1913=413\frac{P}{100}=1-\frac{9}{13}=\frac{4}{13}​​

    P=40013%=301013%P=\frac{400}{13}\%=30\frac{10}{13}\%​​
    ​​

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