A man had a certain amount with him. He spent 30% of that to buy an article and 10% of the remaining on transport, then he donated Rs. 120. If he is left with Rs. 2400. The amount he spent on transport is -

Correct option is A

Given:
The man spent 30% of his total amount to buy an article.
He spent 10% of the remaining amount on transport.
He donated Rs. 120.
He is left with Rs. 2400.

Solution:

Let the initial amount be = 100x

He spent 30% on an article: $$100x \times 30\%$$ = 30x

Remaining amount = 100x - 30x = 70x

Spent 10% of the remaining amount on transport: $$70x \times 10\%$$ = 7x

Remaining amount after transport = 70x - 7x = 63x

​Remaining amount after donation = 63x -120

He is left with Rs. 2400:

63x -120 = 2400

63x = 2520

x = $$\frac{2520}{63}$$

x = 40

Initial amount = 100x = $$100 \times 40$$ = 4,000

He spent 30% on an article and remaining amount = 4000 - 4000 $$\times$$ 30% = 4000 - 1200 = 2,800

Amount spent on transport = 2800 $$\times$$​ 10% = 280

So, the man spent Rs. 280 on transport.

Thus, the correct answer is (a).