A hemispherical bowl made of brass has an inner diameter of 14 cm. Find the cost of painting it from the inside at the rate of 15 per cm².

​$$\left(\pi =\frac{22}7\right)$$​​

Correct option is C

Given:

Inner diameter = 14 cm → Radius r = $$\frac{14}{2}$$​ = 7 cm

Painting rate = ₹15 per cm²

Formula Used:

CSA of hemisphere = 2πr² ​

Solution:

CSA of hemisphere = $$2 \times \frac{22}{7} \times 7^2$$​​

​$$= 2 \times \frac{22}{7} \times 49 = 2 \times 154 = 308 \, \text{cm}^2$$​​

Cost of painting = 308 × 15 = ₹4,620