Correct option is C
Given : + 6 # 5
Number/Symbol | @ | 4 | 6 | 9 | $ | + | 3 | % | # | 7 | & | 5 | $ | 2 |
Code | L | V | C | M | K | P | B | Q | Z | Y | R | B | U | F |
Conditions:
If the first element is a symbol and the last an odd number, the codes for these two (the first and the last elements) are to be interchanged.- Followed .
hence the code for + 6 # 5 = the code for + and 5 interchanged and remaining from the table
code = BCZP
If the first element is an odd number and the last an even number, the first and last elements are to be coded as ©.- Not followed
If both second and third elements are perfect squares, the third element is to be coded as the code for the second element. - Not followed
code = BCZP is answer.
option c correct.