A girl started to walk 2 km in North direction. She turned towards her right and walked 6 km and walked 3 km towards her left. Once again she took a left turn to walk 3 km before taking another left to walk 5 km. How far is she from the starting point?

Correct option is C

Ans. (c) 3 km
Sol. Let's trace her path step-by-step:
1. North 2 km
2. Right → East 6 km
3. Left → North 3 km
4. Left → West 3 km
5. Left → South 5 km
Now compute her final coordinates relative to start:
· Net North = 2 km + 3 km - 5 km = 0 km
· Net East = 6 km - 3 km = 3 km
So, she is 3 km east and 0 km north of the starting point ⇒ Distance = 3 km
Correction: Final step rechecked:
After going south 5 km from 5 km north (2+3), net south = 5 - 5 = 0 km net, error spotted.
Recomputing:
· North = 2 (first) + 3 (after first left) = 5 km
· South = 5 km → Net North-South = 0 km
· East = 6 km (right)
· West = 3 km (third left) → Net East = 6 - 3 = 3 km
So net movement: 3 km East, 0 km vertically Distance = 3 km
Correct Answer: (c) 3 km