A clock marked for Rs.10,000 is available on successive discounts of 40% and k%. If the selling price of the clock is Rs. 2,400, then find the value of k.

Correct option is C

Given:

Marked a price of Clock = Rs. 10000

Selling price of Clock = Rs. 2400

First discount = 40%

Second discount = k%

Concept used:

Successive discounting formula, If two discounts of a% and b% are given,

then Net discount = a + b - $$\frac{(a × b)}{100}$$​​

Solution:

After first discount of 40%, new selling price = Marked price - (Marked price × First discount) = 10000 - (10000 × $$\frac{40}{100}$$​) = Rs. 6000

Let the second discount be k%.

The final selling price after the second discount is given by the equation:

6000 - (6000 × $$\frac{k}{100}$$​) = 2400

6000 − 60k = 2400

6000 − 2400 = 60k

3600 = 60k

k = $$\frac{3600}{60}$$

k = 60%

The value of k is 60

Thus, correct option is (c)