A car manufacturing company is sponsoring a basketball match by painting its logo on the basketball at the rate of ₹3/ $$cm^2$$ . There are two identical basketballs of diameter 14cm which are to be painted. What will be the total cost (in ₹) of painting the balls for the company?

Correct option is D

Given:

The rate of painting is ₹3/cm²

The diameter of the basketballs = 14 cm

There are 2 identical basketballs.

Formula Used:

The surface area of a sphere is given by the formula:

A = 4πr²

Where r is the radius of the sphere.

Solution:

Since the diameter is 14 cm, the radius is:

r = 14 / 2 = 7 cm

Surface area of one basketball:

Using the surface area formula for a sphere:

​$$A = 2 \times 4 \times \frac{22}{7}(7)² = 1232 cm ^2$$​​

The cost of painting per cm² is ₹3, so the total cost is:

Total cost = 1232 × 3 = 3696

Rounding to the nearest whole number, the total cost is ₹3696.