​A body undergoes a displacement of 2 m on application of a constant force of 10 N; the work done will be:​

Correct option is D

The correct answer is (d) 20 J

Explanation:

• Work (W) is defined as the product of force (F) and displacement (d) in the direction of force.
• Mathematically, $$W = F \times d \times \cos\theta$$​

where:

• W = Work done (Joules, J)
• F = Force (Newtons, N)
• d = Displacement (Meters, m)
• ​$$\theta$$​ = Angle between force and displacement

Given:

• Force, F=10N
• Displacement, d=2m
• The angle between force and displacement (force and displacement are in the same direction)

Since cos 0° = 1, the equation simplifies to: W = $$10 \times 2 \times 1$$, W=10×2×1

W=20J

Information Booster:

• Positive Work: When force and displacement are in the same direction (θ = 0°), work is positive.
• Negative Work: When force and displacement are in opposite directions (θ = 180°), work is negative.
• Zero Work: If force is perpendicular to displacement (θ = 90°, e.g., carrying a bag while walking), work done is zero.