A body of mass 5 kg moving with velocity 2 m/s comes to rest within a distance of 6 m. The work done during the process is:

Correct option is A

The correct answer is (a) 10 J.
We can use the work-energy principle, which states that the work done on an object is equal to its change in kinetic energy.
Kinetic energy (KE) = 1/2 * m * v²
The initial kinetic energy is 1/2 * 5 * (2)² = 10 J.
Since the body comes to rest, the final kinetic energy is 0 J.
Thus, the work done is:
W = KE_final - KE_initial = 0 - 10 = -10 J.
The negative sign indicates that the work is done to stop the motion, which is equivalent to a loss of kinetic energy.
Information Booster:
· The work done in stopping the object is negative, as it is against the direction of motion.
· The formula for work is W = F * d, where F is the force and d is the distance. Here, force can be found by using Newton's second law of motion: F = ma.
· Energy is measured in joules (J), where 1 J = 10⁷ erg.