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    A ball of mass m is dropped from a height H. At height H/3, the ratio of its potential energy (PE) to kinetic energy (KE) is equal to:
    Question

    A ball of mass m is dropped from a height H. At height H/3, the ratio of its potential energy (PE) to kinetic energy (KE) is equal to:

    A.

    1/4

    B.

    1

    C.

    1/2

    D.

    1/3

    Correct option is D

    energy is mgh/3mgh=mgh3mgh=13\text{energy is } \frac{mgh/3}{mgh} = \frac{mgh}{3mgh} = \frac{1}{3}​​

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