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A ball of mass m is dropped from a height H. At height H/3, the ratio of its potential energy (PE) to kinetic energy (KE) is equal to:
Question

A ball of mass m is dropped from a height H. At height H/3, the ratio of its potential energy (PE) to kinetic energy (KE) is equal to:

A.

1/4

B.

1

C.

1/2

D.

1/3

Correct option is D

energy is mgh/3mgh=mgh3mgh=13\text{energy is } \frac{mgh/3}{mgh} = \frac{mgh}{3mgh} = \frac{1}{3}​​

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