A bag contains 5 white and 3 black balls. Two balls are drawn at random one after the other, without replacement. The probability that both balls are black is:

Given:
Total balls = 5 white + 3 black = 8 balls
Without replacement
We need probability of both black
Formula used:

P(both black) $$= P(\text{1st black}) \times P(\text{2nd black | 1st black}) \\$$​​
Solution:
P(1st black) =$$\frac{3}{8} \\$$​​
P(2nd black | 1st black}) = $$\frac{2}{7} \\$$​​
​$$\Rightarrow P(\text{both black}) = \frac{3}{8} \times \frac{2}{7} = \frac{6}{56} = \frac{3}{28} \\$$​​
Correct answer is (c)