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    A and B together read 88 pages in 11 hours and efficiency of B is 40% less than A. If A, B and C together can read 150 pages in 10 hours, then find B
    Question


    A and B together read 88 pages in 11 hours and efficiency of B is 40% less than A. If A, B and C together can read 150 pages in 10 hours, then find B and C together can read 120 pages in how many hours.

    A.

    10 hours

    B.

    12 hours

    C.

    8 hours

    D.

    15 hours

    E.

    16 hours

    Correct option is B


    Total pages read by A and B in one hour = 88/11=8
    Let efficiency of A = 5x pages/hour
    So, efficiency of B = 60% of 5x =3x pages/hour
    5x + 3x = 8
    x = 1
    Efficiency of C = 150/10 – (5+3) = 7 pages/hours
    So, required time = 120/((7+3)) = 12 hours

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