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A and B together read 88 pages in 11 hours and efficiency of B is 40% less than A. If A, B and C together can read 150 pages in 10 hours, then find B
Question


A and B together read 88 pages in 11 hours and efficiency of B is 40% less than A. If A, B and C together can read 150 pages in 10 hours, then find B and C together can read 120 pages in how many hours.

A.

10 hours

B.

12 hours

C.

8 hours

D.

15 hours

E.

16 hours

Correct option is B


Total pages read by A and B in one hour = 88/11=8
Let efficiency of A = 5x pages/hour
So, efficiency of B = 60% of 5x =3x pages/hour
5x + 3x = 8
x = 1
Efficiency of C = 150/10 – (5+3) = 7 pages/hours
So, required time = 120/((7+3)) = 12 hours

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