A and B have in their collection, coins of Re. 1. Rs. 2, Rs. 5 and Rs. 10 in the ratio 3:2:2:1 and 4:3:2:1, respectively. The total number of coins with each of them is equal. If the value of coins with A is Rs. 270/-, what is the value of the coins (in Rs) with B?

Correct option is B

Given:

A's ratio: 3:2:2:1 for Re. 1, Rs. 2, Rs. 5, and Rs. 10 coins.

B's ratio: 4:3:2:1 for Re. 1, Rs. 2, Rs. 5, and Rs. 10 coins.

Value of A's coins = Rs. 270.

Formula:
Value of coins = (Re. 1 coins × 1) + (Rs. 2 coins × 2) + (Rs. 5 coins × 5) + (Rs. 10 coins × 10).

Solution:

Let the total number of coins with A be x. Using the ratio 3:2:2:1, the number of each type of coin is:

Re. 1 coins = (3/8) × x.

Rs. 2 coins = (2/8) × x.

Rs. 5 coins = (2/8) × x.

Rs. 10 coins = (1/8) × x.

Total value of coins:
(3/8)x × 1 + (2/8)x × 2 + (2/8)x × 5 + (1/8)x × 10 = 270.
Simplify:
(3x + 4x + 10x + 10x) / 8 = 270.
27x / 8 = 270.
x = 80.

Now, for B, using the ratio 4:3:2:1, the number of each type of coin is:

Re. 1 coins = (4/10) × 80 = 32.

Rs. 2 coins = (3/10) × 80 = 24.

Rs. 5 coins = (2/10) × 80 = 16.

Rs. 10 coins = (1/10) × 80 = 8.

Total value of coins:
32 × 1 + 24 × 2 + 16 × 5 + 8 × 10.
= 32 + 48 + 80 + 80 = 240.

Final Answer:
(b) 240