A 50μf capacitor in a defibrillator is charged to 3000V. The energy stored in the capacitor is sent through the victim during a pulse of duration 2 ms; the power of the pulse is close to:

Correct option is C

​$$\textbf{Given:} \\\bullet \text{Capacitance, } C = 50\, \mu F = 50 \times 10^{-6}\, F \\\bullet \text{Voltage, } V = 3000\, V \\\bullet \text{Time, } t = 2\, ms = 2 \times 10^{-3}\, s\\[10pt] \text{Energy stored in a capacitor:} \quad E = \frac{1}{2} C V^2 \\ \text{Power:} \quad P = \frac{E}{t}\\[10pt]\textbf{ Energy} \\E = \frac{1}{2} \times 50 \times 10^{-6} \times (3000)^2 \\E = 25 \times 10^{-6} \times 9 \times 10^6 = 225\, J\\[10pt]\textbf{ Power} \\P = \frac{225}{2 \times 10^{-3}} = 112500\, W = 112.5\, \text{kW}$$​​