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    A 200 g block of iron was heated from 30°C to 60°C How much heat was transferred to the block (specific heat of iron is 450 J kg⁻¹K⁻¹)?
    Question

    A 200 g block of iron was heated from 30°C to 60°C How much heat was transferred to the block (specific heat of iron is 450 J kg⁻¹K⁻¹)?

    A.

    6000 J

    B.

    2700 J

    C.

    270 J

    D.

    27 J

    Correct option is B


    The amount of heat Q absorbed or released when a material changes temperature is given by:
    Q = m × c × ΔT,
    where m is the mass in kilograms, c is the specific heat capacity (J kg⁻¹K⁻¹), and ΔT is the change in temperature in Kelvin or °C. Here:
    · m = 200g = 0.2 kg
    · c = 450 J kg⁻¹K⁻¹ (for iron)
    · ΔT = 60 – 30 = 30 K
    So,
    Q = 0.2 × 450 × 30
    First calculate 0.2 × 450 = 90.
    Then 90 × 30 = 2700 J.

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