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A 1 metre long conductor carries a current of 40A at right angles to a magnetic field of 100×10-3 Tesla. The force on the conductor is:
Question

A 1 metre long conductor carries a current of 40A at right angles to a magnetic field of 100×10-3 Tesla. The force on the conductor is:

A.

4 Newton

B.

400 Newton

C.

0.4 Newton

D.

40 Newton

Correct option is A

Explanation:The force F on a conductor in a magnetic field is given by the equation:\textbf{Explanation:} \text{The force } F \text{ on a conductor in a magnetic field is given by the equation:}​​F=BILF = B \cdot I \cdot L

where:\textbf{where:}

B is the magnetic field strength (in Tesla),I is the current (in Amperes),L is the length of the conductor (in meters).\begin{array}{ll}\bullet \quad B \text{ is the magnetic field strength (in Tesla),} \\\bullet \quad I \text{ is the current (in Amperes),} \\\bullet \quad L \text{ is the length of the conductor (in meters).}\end{array}

Given:\textbf{Given:}

B=100×103 Tesla=0.1 Tesla,I=40 A,L=1 m.\begin{array}{ll}\bullet \quad B = 100 \times 10^{-3} \text{ Tesla} = 0.1 \text{ Tesla}, \\\bullet \quad I = 40 \text{ A}, \\\bullet \quad L = 1 \text{ m}.\end{array}

F=0.1 T×40 A×1 m=4 NF = 0.1 \text{ T} \times 40 \text{ A} \times 1 \text{ m} = 4 \text{ N}​​

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