Correct option is DWe know that\text{We know that}We know that(F−32)×59=C(Celsius)(F - 32) \times \frac{5}{9} = C \quad \text{(Celsius)}(F−32)×95=C(Celsius)(95−32)×59=C(95 - 32) \times \frac{5}{9} = C(95−32)×95=C=>63×59=C\Rightarrow 63 \times \frac{5}{9} = C=>63×95=C=>7×5=C\Rightarrow 7 \times 5 = C=>7×5=CC=35C = 35C=35