What will come in place of the question mark (?) in the following questions?
75
60
45
60+40=? 100=?
Value of0.97×0.97×0.97+0.03×0.03×0.030.97×1.94−1.94×0.03+0.03×0.06 \frac{0.97 \times 0.97 \times 0.97 + 0.03 \times 0.03 \times 0.03}{0.97 \times 1.94 - 1.94 \times 0.03 + 0.03 \times 0.06}0.97×1.94−1.94×0.03+0.03×0.060.97×0.97×0.97+0.03×0.03×0.03 is equal to:
The value of (0.29‾÷0.32‾)×6.60.95‾÷1.05‾×1.2‾\frac{(0.\overline{29} \div 0.\overline{32}) \times 6.6}{0.\overline{95} \div 1.\overline{05} \times 1.\overline{2}}0.95÷1.05×1.2(0.29÷0.32)×6.6 is
4110−[212−{56−(25+310−415)}]4\frac{1}{10}-\left[2\frac{1}{2}-\left\{\frac{5}{6}-\left(\frac{2}{5}+\frac{3}{10}-\frac{4}{15}\right)\right\}\right]4101−[221−{65−(52+103−154)}]on simplification gives
Find the value of [(36÷9)×{568+141×(6−5)}]\left[\left(36 \div 9\right) \times \left\{\frac{56}{8} + \frac{14}{1} \times (6 - 5)\right\}\right][(36÷9)×{856+114×(6−5)}]
The value of 25+(11+57)−25\frac{2}{5}+\left(\frac{1}{1+\frac{5}{7}}\right)-\frac{2}{5}52+(1+751)−52
Find the value of (168)×{402+116×(8−2)}\left( \frac{16}{8} \right) \times \left\{ \frac{40}{2} + \frac{11}{6} \times (8 - 2) \right\}(816)×{240+611×(8−2)}
Simplify: [(23)+(45÷27)]÷[(32)−(56×34)]\left[\left(\frac{2}{3}\right)+\left(\frac{4}{5}\div \frac{2}{7}\right)\right]\div \left[\left(\frac{3}{2}\right)-\left(\frac{5}{6}\times \frac{3}{4}\right)\right][(32)+(54÷72)]÷[(23)−(65×43)]
Simplify: (212+3.6)÷0.75+(1.25×45)\left(2\frac{1}{2} + 3.6\right) \div 0.75 + \left(1.25 \times \frac{4}{5}\right)(221+3.6)÷0.75+(1.25×54)
Simplify: (75÷1415)×(107÷53)\left( \frac{7}{5} \div \frac{14}{15} \right) \times \left( \frac{10}{7} \div \frac{5}{3} \right)(57÷1514)×(710÷35)
Simplify: (1.5+38)3−(95×1.25)\left( 1.5 + \frac{3}{8} \right)^{3} - \left( \frac{9}{5} \times 1.25 \right)(1.5+83)3−(59×1.25)
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