​$$\frac{2^5 \times 4^3}{8^2 \times 2^2}$$​​

Correct option is A

Given:

$$\frac{2^5 \times 4^3}{8^2 \times 2^2}$$

​Formula used:​

$$a^m \times a^n = a^{m + n}$$

$$\frac{a^m}{a^n} = a^{m - n}$$

$$(a^m)^n = a^{m \times n}$$​​​​

Solution:

$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline \text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & (power), √ (root) , of \\ \hline \text{Division}& ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline \end{array}$$​

​$$\frac{2^5 \times 4^3}{8^2 \times 2^2}$$

= $$\frac{2^5 \times 2^{2\times3}}{2^{3\times2} \times 2^2}$$

= $$\frac{2^5 \times 2^{6}}{2^{6} \times 2^2}$$

= $$2^{5+6-6-2}$$

= $$2^3$$

= 8

Thus, the correct answer is (a).