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    1 is subtracted from each even digit of the number 95423671. Find the number of digits that are repeated more than once in the new number formed
    Question

    1 is subtracted from each even digit of the number 95423671. Find the number of digits that are repeated more than once in the new number formed

    A.

    None 

    B.

    One 

    C.

    Two

    D.

    Three

    Correct option is D

    Given :

    Number = 95423671

    Solution :
    Even digit − 1

    Even digits in 95423671 = 4, 2, 6
    After subtracting 1 → 3, 1, 5

    New number formed = 95313571

    Digit frequency:

    1 → 2 times

    3 → 2 times

    5 → 2 times

    Digits repeated more than once = 3

    Answer: 3

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