1 is subtracted from each even digit of the number 95423671. Find the number of digits that are repeated more than once in the new number formed
Given :
Number = 95423671
Solution :
Even digit − 1
Even digits in 95423671 = 4, 2, 6
After subtracting 1 → 3, 1, 5
New number formed = 95313571
Digit frequency:
1 → 2 times
3 → 2 times
5 → 2 times
Digits repeated more than once = 3
Answer: 3
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