Correct option is C
Solution:
Let x=1.23657657657…∴x can be written as x=1.23657—-(A)This number has three repeating numbers, so we will multiply 102 in equation (A)100x=123.657—-(1)Again, multiply 105 in equation (A)100000x=123657.657—-(2)Subtract equation (1) from equation (2):=>99900x=123534∴x=99900123534