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# Quantitative Aptitude Daily Quiz In Marathi | 18 June 2021 | For IBPS RRB PO/Clerk

Quantitative Aptitude दैनिक क्विझ मराठीमध्ये: 18 जून 2021

IBPS RRB च्या परीक्षांसाठी Quantitative Aptitude आणि Reasoning या विषयात चांगले गूण मिळवण्यासाठी जास्तीत जास्त सराव करणे खूप गरजेचे असते. तर चला Quantitative Aptitude बद्दल तुमची तयारी तपासण्यासाठी खालील 18 जून 2021 ची Quantitative Aptitude ची दैनिक क्विझ पहा.

Subject:  Revision Test

Directions (1-5): Solve the following equations and mark the correct option given below.
(a) if x>y
(b) if x≥y
(c) if y>x
(d) if y≥x
(e) if x=y or no relation can be established
Q1. I. 6x² + 7x + 2 = 0
II. 3y² + 8y + 5 = 0

Q2. I. 7x² – 23x + 6 = 0
II. y² – 7y + 12 = 0

Q3. I. 5x² + 13x – 6 = 0
II. 2y² + 13y – 7 = 0

Q4. I. 4x + 3y = 4
II. 6x + 5y = 8

Q5. I. x² – 19x + 88 = 0
II. y² + y – 56 = 0

Directions (6-10): What will come at the place of question mark?
Q6. 92, 117, 217, 442, 842, ?
(a) 1367
(b) 1397
(c) 1457
(d) 1467
(e) 1497

Q7. ?, 212, 339, 508, 725, 996
(a) 120
(b) 121
(c) 116
(d) 115
(e) 125

Q8. 4, 6, 9, 13.5, 20.25, ?
(a) 30.375
(b) 30.275
(c) 29.375
(d) 32.375
(e) 32.275

Q9. 81, ? , 155, 276, 445, 734
(a) 105
(b) 104
(c) 106
(d) 110
(e) 112

Q10. 5986, 2996, 1502, 756, ? , 199
(a) 264
(b) 284
(c) 354
(d) 374
(e) 384

Directions (11-15): Find the approximate value of given questions.
Q11. 1782.011 ÷ 53.99 + 455.889 – 2346.011 × 1.011 = ? × 2.93
(a) –629
(b) –619
(c) 629
(d) 619
(e) –609

Q12. (574.99 + 7511.11 – 2768.91) ÷ (76.1 × 0.98 + 674.976 – 342.001) = √(?)
(a) 529
(b) 49
(c) 169
(d) 289
(e) 729

Q13. [(√(3843.9×9.09))÷(26.99)^(1/3) ]×23.012=?^2+336.97
(a) 33
(b) 23
(c) 27
(d) 37
(e) 43

Q14. √((95.99)×12.01÷17.9+25.899–9.011)=(64.9–?)% of 35.88
(a) 50
(b) 35
(c) 30
(d) 40
(e) 20

Q15. 11.9×√224.89+1212.09 –(1053.11÷8.9) = ?
(a) 1,275
(b) 1,225
(c) 1,175
(d) 1,255
(e) 1,245

Directions (16-20): What value should come in place of (?) in the following questions?
Q16. √12.25 × 18 – (?)² = (6)² + √4
(a) 7
(b) 6
(c) 5
(d) 4
(e) 3

Q17. (1250 + 1725) ÷ (825 + 365) = ?
(a) 1.5
(b) 2.5
(c) 1
(d) 2.25
(e) 2.75

Q18. √625 ÷ √16 × 6 = ?% of 300
(a) 15
(b) 12.5
(c) 17.5
(d) 10
(e) 8.5

Q19. 26 × 15 + 310 – (15)² = 25% of ?
(a) 1600
(b) 1800
(c) 1900
(d) 1500
(e) 1700

Q20. √81 × √625 + 1225 = (?)² – 150
(a) 50
(b) 45
(c) 35
(d) 30
(e) 40

महाराष्ट्र राज्यातील सर्व स्पर्धा परीक्षांचे मोफत अभ्यास साहित्य

Solution

S1. Ans.(a)
Sol.
I. 6x² + 7x + 2 = 0
6x² + 3x + 4x + 2 = 0
3x (2x + 1) + 2 (2x + 1) = 0
x = (–1)/2, (–2)/3
II. 3y² + 8y + 5 = 0
3y² + 5y + 3y + 5 = 0
y(3y + 5) + 1 (3y + 5) = 0
y=–1,(–5)/3
x > y

S2. Ans.(d)
Sol.
I. 7x² – 23x + 6 = 0
7x² – 21x – 2x + 6 = 0
7x (x – 3) – 2 (x – 3) = 0
x=3,2/7

II. y² – 7y + 12 = 0
y² – 3y – 4y + 12 = 0
y(y – 3) – 4 (y – 3) = 0
y = 3, 4
y ≥ x

S3. Ans.(e)
Sol.
I. 5x² + 13x – 6 = 0
5x² + 15x – 2x – 6 = 0
5x (x + 3) – 2 (x + 3) = 0
x=2/5, –3

II. 2y² + 13y – 7 = 0
2y² + 14y – y – 7 =0
2y ( y + 7) – 1 (y + 7) = 0
y = –7, 1/2

No relation

S4. Ans.(c)
Sol.
I. 4x + 3y = 4 …(i)
II. 6x + 5y = 8 …(ii)
Multiplying (i) by 5 and (ii) by 3 & subtracting (ii) from (i), we get
x = –2
put x=-2 in (i), we get
y = 4
y > x

S5. Ans.(a)
Sol.
I. x² – 19x + 88 = 0
x² – 11x – 8x + 88 = 0
x (x – 11) – 8 (x – 11) = 0
x = 8, 11

II. y² + y – 56 = 0
y² + 8y – 7y – 56 = 0
y (y + 8) – 7 (y + 8) = 0
y = 7, – 8
x > y

S6. Ans.(d)
Sol.

S7. Ans.(b)
Sol.

S8. Ans.(a)
Sol.

S9. Ans.(c)
Sol.

S10. Ans.(e)
Sol.

S11. Ans.(b)
Sol.
1782 ÷ 54 + 456 – 2346 × 1 = ? × 3
⇒ 33 + 456 – 2346 = ? × 3
⇒ – 1857 = ? × 3
⇒ ?=(–1857)/3
= –619

S12. Ans.(c)
Sol.
(575+7511 –2769)÷(76×1+675 –342)=√(?)
= 5317÷409=√(?)
⇒ ? = (13)^2 = 169

S13. Ans.(a)
Sol.
[(√(3844×9))÷(27)^(1/3) ]×23=?^2+337
⇒[(62×3)÷3]×23=?^2+337
⇒ 1426 – 337 = ?²
⇒ ? = √1089
= 33

S14. Ans.(d)
Sol.
=√((96)×12÷18+26 –9) = (65 –?)% of 36
⇒9=((65 –?))/100×36⇒(65 –?)=(9×100)/36
⇒ ? = 65 – 25 = 40

S15. Ans.(a)
Sol.
12×√225+1212 –(1053÷9) = ?
⇒ 1392 – (117) = ?
⇒ ? = 1275

S16. Ans.(c)
Sol.
3.5 × 18 – (?)² = 36 + 2
63 – 38 = (?)²
25 = (?)²
? = 5

S17. Ans.(b)
Sol.
?=2975/1190
? = 2.5

S18. Ans.(b)
Sol.
(25÷4×6)/3= ?
? = 12.5

S19. Ans.(c)
Sol.
(390 + 310 – 225) 4 = ?
(700 – 225) 4 = ?
475 × 4 = ?
? = 1900

S20. Ans.(e)
Sol.
9 × 25 + 1225 + 150 = (?)²
225 + 1225 + 150 = (?)²
? = √1600
? = 40

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