ম্যাথমেটিক্স MCQ: Adda 247-এ আপনাকে স্বাগতম। Adda 247 বাংলা আপনাকে WBCS, WBSSC, WBP, WBPSC, RAIL,SSC এবং BANK সহ সমস্ত প্রতিযোগিতামূলক পরীক্ষার জন্য বাংলায় ম্যাথমেটিক্স MCQ দিচ্ছে। এখানে আপনি প্রতিদিন সমাধান সহ একাধিক পছন্দের প্রশ্ন এবং উত্তর পাবেন। এখানে আপনি সমস্ত গুরুত্বপূর্ণ প্রশ্ন এবং উত্তর পাবেন যা আপনাকে আপনার জ্ঞান বাড়াতে এবং আপনাকে আপনার লক্ষ্য পূরণের দিকে এগিয়ে যেতে সাহায্য করবে। এই ম্যাথমেটিক্স MCQ নিয়মিত পড়ুন এবং পরীক্ষায় সফল হন।
| ম্যাথমেটিক্স MCQ | |
| বিষয় | ম্যাথমেটিক্স MCQ |
| বিভাগ | Daily Quiz |
| উদ্দেশ্য | IBPS RRB পরীক্ষা |
ম্যাথমেটিক্স MCQ
Q1. Veer invested Rs. 18000 at the rate of 20% on C.I. and Akshita invested Rs. 16000 at the rate of 30% on S.I. Find the difference between interest obtained by Veer and Akshita at the end of two years.
(a) Rs. 1680
(b) Rs. 1720
(c) Rs. 1620
(d) Rs. 1780
(e) Rs. 1580
Q2. Ratio of age Ram and Shyam 10 years ago was 3 : 4. Ratio between age of Ram 4 year hence and Shyam’s age 6 years hence is 11 : 14. Find the sum of present age of Ram and Shyam.
(a) 88 years
(b) 96 years
(c) 86 years
(d) 94 years
(e) 90 years
Q3. The area of a circle is equal to the area of a rectangle whose perimeter is 42 m and breadth is 8.5 m. What is the area of the circle ?
(a) 116.25 sq m
(b) 104.25 sq m
(c) 146.25 sq m
(d) 128.25 sq m
(e) None of these
Q4. A and B invested Rs. 12000 and Rs15000 in a business partnership. A invested his amount for ‘x’ months. If at the end of year ratio of profit share of A to B is 2 : 3 then find the value of x.
(a) 11
(b) 7
(c) 9
(d) 10
(e) 8
Q5. Two classes A and B of a school have 420 and 600 students respectively. If ratio of boys from school A to B is 16 : 25 and total girls in both school is 405. Calculate boys from school A are what percent of total girls from both school.
(a) 54 7/27%
(b) 55 3/27%
(c) 59 7/27%
(d) 59 2/27%
(e) 57 7/27%
Q6. 180 m long Train A crosses Train B of 120 m in length which is running in opposite direction in 5 5/11 sec. If speed of train B is 20% more than that of train A, then find the time taken by both trains to cross each other, when they running in same direction?
(a)60 sec
(b)58 sec
(c)55 sec
(d)50sec
(e)65 sec
Q7. ‘X’ meters long train cross a pole in ‘t’ sec and a platform which is ‘L’ meters long in 20 sec. If speed of train is 72 km/hr, then what will be value of ‘t’ and ‘L’
(a) 16 & 140
(b) 12 & 200
(c) 8 & 240
(d) 8 & 200
(e) 16 & 120
Q8. Train ‘X’ takes 2 hours more than train ‘Y’ to cover certain distance ‘D’ while train ‘X’ can cover (D + 160) is 8 hours. If speed of train ‘Y’ is 50% more than that of train ‘X’, then find the speed of train ‘Y’?
(a) 80 km/hr
(b) 120 km/hr
(c) 16 km/hr
(d) 40 km/hr
(e) 60 km/hr
Q9. Ratio between length of two trains is 1 : 2 and speed of two trains is 120 km/hr & 108 km/hr respectively and both trains running in same direction cross each other in 108 sec. If two compartments were added in smaller train then it can cross a platform of length of 12.5 times of length of one compartment in 14.04 sec, then find the time taken by longer train to cross that same platform, if five new compartments were added in to that train?
(a) 18 sec
(b) 22 sec
(c) 16 sec
(d) 20 sec
(e) 28 sec
Q10. Two trains A and B of length 400 m and (400 + x) m respectively are moving with same speed. If train A and B crosses a pole in 16 sec and 24 secs respectively then in what time train ‘B’ will cross 400 m long platform.
(a) 32 sec
(b) 40 sec
(c) 45 sec
(d) 54 sec
(e) 24 sec
ম্যাথমেটিক্স MCQ সমাধান
S1. Ans.(a)
Sol.
Equivalent CI for 2 years at the rate of 20%
= 20+20+(20×20)/100
= 44%
Equivalent SI for 2 years at the rate of 30%
= 2 × 30%
= 60%
Required difference = 60/100×16000 –44/100×18000
= 60 × 160 – 44 × 180
= 9600 – 7920
= 1680
S2. Ans.(e)
Sol.
Let present age of Ram and Shyam be R and S respectively
(R–10)/(S–10)=3/4
4R–40=3S–30
4R–3S=10 …(i)
(R+4)/(S+6)=11/14
14R+56=11S+66
14R–11S=10 …(ii)
Solving (i) and (ii)
S = 50 year and R = 40 years
Required sum = 90 years
S3. Ans.(e)
Sol.
Perimeter of the rectangle = 42 m
2(L + B) = 42 m
or, L + 8.5 = 21 m
or, L = 12.5 m
Area of the rectangle = 12.5 × 8.5 = 106.25 sq m
∴ Area of the circle = 106.25 sq m
S4. Ans.(d)
Sol.
According to question
(12×x)/(15×12)=2/3
x/15=2/3
x= 10 months
S5. Ans.(c)
Sol.
Let boys in both sschools are 16x and 25x respectively
So,
16x+25x=(600+420) –405
41x=615
x=15
Required % = (15×16)/405×100
= 1600/27%
= 59 7/27%
S6. Ans.(a)
Sol.
Let speed of train A be 5x km/hr
Then speed of train B=6x km/hr
ATQ—
(6x+5x)×5/18=(120+180)/(60/11)
x = 18
Required time==(120+180)/((108-90)×5/18)=60 sec
S7. Ans(c)
Sol.
Speed of train in m/s = 72 ×5/18=20 m/s
ATQ –
20=X/t
Or, X = 20t ————– (i)
Also,
20 = (X +L)/20
X + L = 400
X = 400 – L ————- (ii)
From (i) & (ii)
20t = 400 – L ———— (iii)
Only (c) satisfied the equation (iii)
S8. Ans.(b)
Sol.
Let speed of train ‘X’ = x km/hr
And, speed of train ‘Y’ = 1.5x km/hr
ATQ,
2=D/x-D/1.5x …(i)
And, (D+160)/8=x …(ii)
On solving (i) & (ii)
x = 80 kmph
speed of train ‘Y’ = 120 kmph
S9. Ans(b)
Sol.
Let length of two train is l & 2l respectively
ATQ –
(120 – 108)× 5/18=(l+2l)/108
10/3=l/36
l = 120 m
Length of longer train = 2 ×120= 240 m
Let length of each compartment be x m
So,
120 ×5/18=(120+2×x+12.5×x)/10.04
100/3=(120+14.5x)/14.04
1404 = 360 + 43.5x
43.5 = 1044
x = 24 m
Length of platform = 24 ×12.5=300 m
New length of longer train = 240 + 5 ×24=360 m
Let time taken by longer train = t sec
108 ×5/18=(360+300)/t
t = 660/30
t = 22 sec
S10. Ans.(b)
Sol.
Speed of train A = 400/16 = 25 m/sec
So, speed of train B = 25 m/sec
ATQ,
(400+x)/25 = 24
x= 200 m
Now time required to cross platform by B
= (400+200+400)/25 = 40 sec
