Bank Exams Reasoning Questions with Detailed Solutions

=
A ≥ B = C = D = F < E
A ≥ F True
E > B True

ZW
KN K+3 N
BE B+3 E
VY V+3 Y
ZW Z-3 W
RU R+3 U

Neither conclusion I nor II is true
Solution
Given Statements: L = K ≥ P ≥ U; Z ≥ M = L
On combining the statements, we get
Z ≥ M = L = K ≥ P ≥ U
Conclusions:
I. Z > U: False (As, Z ≥ M = L = K ≥ P ≥ U, so, Z ≥ U)
II. M ≤ P: False (As, M = L = K ≥ P, so, M ≥ P)
Therefore, neither conclusion I nor II is true.

Three
Given Word: 'VERSATILE'.
There are three pairs ('RS', 'AE', and 'SV') in the word, which has as many letters between them (both forward and backward) as in the English Alphabetical Series.
Hence, option b.

9
Solution
Given number: 285393714
After replacement, we get: 1 23345 789
The third digit from the right end is: 7
The eighth digit from the right end is: 2
So, the sum of third and eighth digit from the right end is: 7 + 2 = 9

Only conclusion I follows
Following figure can be formed:

Conclusions:
I. No Lily is Rose: This definitely follows as only Red is Lily.
II. Some Red not being Rose is a possibility: This definitely doesn't follow as only Red is Lily, so, some Red can never be Rose, which is definite.
From the above figure, only conclusion I follows.

Z
Solution
Answer: E
The letters are P, O, S and T. So the newly formed meaningful words are POST, STOP.

Two
Solution
Answer: B

Both I and II follows
Explanation:

I) Some Angels are Devil is a possibility→True
II) All God is Angel is a possibility→True
Hence Both I and II follows.

>
1) ≤ → P > L ≤ A ≥ N = T (P > A is False)
2) > → P > L > A ≥ N = T (P > A and L > T is True)
3) < → P > L < A ≥ N = T (P > A is False)
4) ≥ → P > L ≥ A ≥ N = T (L > T is not defenitely true)
5) Either ≥ or >
Therefore, > will make the expression P > A and T < L definitely true.

=, =, =, ≥
1) =, =, ≥, ≥
U = N = C ≥ L ≥ E
U ≥ E → possibly true (as U ≥ L ≥ E)
C = L → false (C ≥ L)
2) >, ≥, =, >U > N ≥ C = L > E
U ≥ E → false (as U > E)
C = L → true (C = L)
3) =, =, =, ≥
U = N = C = L ≥ E
U ≥ E → true (U = L ≥ E)
C = L → true (C = L)
4) >, =, <, ≥
U > N = C < L ≥ E
U ≥ E → false (the relationship between U and E cannot be defined)
C = L → false (C < L)
So =, =, =, ≥ symbols complete the given expression in such a manner that makes the expressions ‘U ≥ E’ as well as ‘C = L’ definitely true
Hence, option ‘ =, =, =, ≥ ’ is the correct option.

S < T; A ≥ B > P ≥ T > R; K < M < S
S < T; A ≥ B > P ≥ T > R; K < M < S
Explanation:
From option a, K < M < S < T ≤ P < B ≤ A
From option b, K < M > S < T ≤ P < B ≤ A
From option c, K < M < S < T > P < B ≤ A
From option d, K < M < S > T > P < B ≤ A

Y ≤ M < C; D ≤ E < F; C < B ≤ A < D
Y ≤ M < C; D ≤ E < F; C < B ≤ A < D
Explanation:
From option a, Y ≤ M < C < B ≤ A > D ≤ E < F
From option b, Y ≤ M ≥ C > B ≤ A < D ≤ E < F
From option c, Y > M < C < B ≤ A < D > E < F
From option d, Y ≤ M < C < B ≤ A < D ≤ E < F

Only <