You are configuring a network and need to assign the IP address 10.192.0.79 to a device. If the subnet mask is 255.255.255.0, which of the following statements is TRUE?

Correct option is A

To determine the correct answer, let's analyze step by step:
1. Subnet Information:
· The given subnet mask is 255.255.255.0, which translates to /24.
· This means the subnet includes all IP addresses in the range 10.192.0.0 to 10.192.0.255.
2. Broadcast Address:
· For a /24 subnet, the broadcast address is always the last IP in the range.
· In this case, the broadcast address is 10.192.0.255.
3. Network Address:
· The network address is the first IP in the subnet range.
· In this case, the network address is 10.192.0.0.
4. Valid Host IPs:
· Valid host IPs are all the addresses between the network address and the broadcast address, excluding both.
· For this subnet, the valid host IP range is 10.192.0.1 to 10.192.0.254.
5. Analysis of the IP Address 10.192.0.79:
· The IP 10.192.0.79 falls within the valid host range (10.192.0.1 to 10.192.0.254).
· Therefore, it is a valid host address in the subnet 10.192.0.0/24.
Important Key Points:
· A /24 subnet contains 256 total IPs, where the first is the network address, the last is the broadcast address, and the rest are valid host IPs.
· Always calculate the subnet range carefully to determine if an IP belongs to the network.
Knowledge Booster:
1. Subnet Mask Notation:
· 255.255.255.0 = /24 = 256 total IPs.
· Subnet masks define how many bits are reserved for the network portion of the address.
2. Broadcast Address:
· It is used for communication with all devices in a subnet and is always the last IP in the subnet range.
3. Host IPs:
· Host IPs are the usable addresses within the subnet, excluding the network and broadcast addresses.