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​x2+92+345=39x^2 + \frac{9^2 + 34}{5} = 39x2+592+34​=39​​
Question

Calculate the exact value of the ‘x’ in the given following questions


x2+92+345=39x^2 + \frac{9^2 + 34}{5} = 39​​

A.

5

B.

4

C.

8

D.

6

E.

9

Correct option is B

x2+81+345=39x2+1155=39x2=3923=16x=4x^2 + \frac{81 + 34}{5} = 39 \\x^2 + \frac{115}{5} = 39 \\x^2 = 39 - 23 = 16 \\x = 4​​​​​

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