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    Which two signs should be interchanged to make the given equation correct?23 ×\times× 7 - 76 + 87 ÷\div÷ 344 = 2​
    Question

    Which two signs should be interchanged to make the given equation correct?
    23 ×\times 7 - 76 + 87 ÷\div 344 = 2​

    A.

    ×\times and ÷\div​​

    B.

    ÷\div and =​

    C.

    ×\times and -​

    D.

    + and ×\times​​

    Correct option is B

    Given: 23 ×\times 7 - 76 + 87 ÷\div 344 = 2
    Logic: Interchange the signs in the given equation as per the options and then solve the equation using the BODMAS rule.
    Operation preference wiseSymbolBrackets[],,()Orders,of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{ | c | c | } \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[], {}, () \\ \hline Orders, of & (power), √ (root), of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}​​
    First option: ×\times and ÷\div
    After interchanging the signs, we get, 23 ÷\div​ 7 - 76 + 87 ×\times 344 = 2
    3.28 - 76 + 87 ×\times 344 = 2
    3.28 - 76 + 29928 = 2
    29931.28 - 76 = 2
    29855.28 \neq 2 (This option does not satisfy the equation.)​
    Second option: ÷\div and =
    ​After interchanging the signs, we get, 23 ×\times 7 - 76 + 87 = 344 ÷\div 2
    23 ×\times 7 - 76 + 87 = 172
    161 - 76 + 87 = 172
    248 - 76 = 172
    172 = 172 (This option satisfies the equation.)
    Third option: ×\times and -
    ​After interchanging the signs, we get, 23 - 7 ×\times 76 + 87 ÷\div 344 = 2
    23 - 7 ×\times 76 + 0.25 = 2
    23 - 532 + 0.25 = 2
    23.25 - 532 = 2
    -508.75 \neq 2 (This option does not satisfy the equation.)​​
    Fourth option: + and ×\times
    ​After interchanging the signs, we get, 23 + 7 - 76 ×\times 87 ÷\div 344 = 2
    23 + 7 - 76 ×\times 0.25 = 2
    23 + 7 - 19 = 2
    30 - 19 = 2
    11 \neq 2 (This option does not satisfy the equation.)​
    So, only the second option follows the given equation.
    Thus, the correct answer is (b).

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