​Which two signs should be interchanged to make the following equation correct?

658 × 14 ÷ 3 − 32 + 56 = 165​

Logic: interchange mathematical operators and solve as per BODMAS rule.

​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & (power), √ (root) , of \\ \hline Division& ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\\hline \end{array}$$​​

658 × 14 ÷ 3 − 32 + 56 = 165

After interchanging,

658 × 14 + 3 − 32 ÷ 56 = 165

Here, 32 is perfectly not divisible by 56.

So, its not correct option.

658 × 14 ÷ 3 − 32 + 56 = 165

After interchanging,

658 × 14 - 3 ÷ 32 + 56 = 165

Here, 3 is perfectly not divisible by 32.

So, its not correct option.

658 × 14 ÷ 3 − 32 + 56 = 165

After interchanging,

658 ÷ 14 × 3 − 32 + 56 = 165

47 × 3 − 32 + 56 = 165

141 − 32 + 56 = 165

658 × 14 ÷ 3 − 32 + 56 = 165

After interchanging,

658 × 14 = 3 − 32 + 56 ÷ 165

Here, 56 is perfectly not divisible by 165.

So, its not correct option.

Thus, correct option is (c).