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Which two signs should be interchanged to make the following equation correct?48÷16×24-5+3=12​​
Question

Which two signs should be interchanged to make the following equation correct?
48÷16×24-5+3=12​​

A.

÷ and ×

B.

÷ and +

C.

− and ÷

D.

+ and ×

Correct option is D

Logic: interchange mathematical operators and solve as per BODMAS rule.
Operation preference wiseSymbolBrackets[],,()Orders,of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & (power), √ (root) , of \\ \hline Division& ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\\hline \end{array}​​
Check option A,÷ and ×
Given:
48÷16×24-5+3=12
After interchanging,
48×16÷24-5+3=12
32-5+3=12
30≠12
So, its not correct option.
Check option B, ÷ and +
Given:
48÷16×24-5+3=12
After interchanging,
48+16×24-5÷3=12
Here, 5 is perfectly not divisible by 3.
So, its not correct option.
Check option C,− and ÷
Given:
48÷16×24-5+3=12
After interchanging,
48-16×24÷5+3=12
Here, 24 is perfectly not divisible by 5.
So, its not correct option.
Check option D,+ and ×
Given:
48÷16×24-5+3=12
After interchanging,
48÷16+24-5×3=12
3+24-15=12
12=12
So, its correct option.
Thus, correct option is (d).

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