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    Which two signs should be interchanged to make the following equation correct?48÷16×24-5+3=12​​
    Question

    Which two signs should be interchanged to make the following equation correct?
    48÷16×24-5+3=12​​

    A.

    ÷ and ×

    B.

    ÷ and +

    C.

    − and ÷

    D.

    + and ×

    Correct option is D

    Logic: interchange mathematical operators and solve as per BODMAS rule.
    Operation preference wiseSymbolBrackets[],,()Orders,of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & (power), √ (root) , of \\ \hline Division& ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\\hline \end{array}​​
    Check option A,÷ and ×
    Given:
    48÷16×24-5+3=12
    After interchanging,
    48×16÷24-5+3=12
    32-5+3=12
    30≠12
    So, its not correct option.
    Check option B, ÷ and +
    Given:
    48÷16×24-5+3=12
    After interchanging,
    48+16×24-5÷3=12
    Here, 5 is perfectly not divisible by 3.
    So, its not correct option.
    Check option C,− and ÷
    Given:
    48÷16×24-5+3=12
    After interchanging,
    48-16×24÷5+3=12
    Here, 24 is perfectly not divisible by 5.
    So, its not correct option.
    Check option D,+ and ×
    Given:
    48÷16×24-5+3=12
    After interchanging,
    48÷16+24-5×3=12
    3+24-15=12
    12=12
    So, its correct option.
    Thus, correct option is (d).

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