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Which two signs need to be interchanged to make the following equation correct?36 + 6 ÷ 3 - 20 × 5 = 50
Question

Which two signs need to be interchanged to make the following equation correct?
36 + 6 ÷ 3 - 20 × 5 = 50

A.

+ and -

B.

- and ÷

C.

× and ÷

D.

+ and ×

Correct option is C

Operation preference wiseSymbolBrackets[],,()Orders, of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline\textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & (power), √ (root) , of \\ \hline \text{Division}& ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}​​
Given:
36 + 6 ÷ 3 - 20 × 5 = 50
Check each options:
Option A: Interchanged + and -
36 − 6 ÷ 3 + 20 × 5 = 50
= 36 - 2 + 20 × 5 = 50
= 36 - 2 + 100 = 50
= 136 - 2 = 50
= 134 \not= 50
Option B: Interchanged - and ÷
36 + 6 − 3 ÷ 20 × 5 = 50
= 36 + 6 − 0.15 × 5 = 50
= 36 + 6 − 0.75 = 50
= 42 -0.75 = 50
= 41.25 \not=​ 50
​Option C: Interchanged × and ÷
36 + 6 × 3 − 20 ÷ 5 = 50
= 36 + 18 − 4 = 50
= 54 - 4 = 50
= 50 = 50 (Follow)
Option D: Interchanged + and ×
36 × 6 ÷ 3 − 20 + 5 = 50
= 36 × 2 - 20 + 5 = 50
= 72 + 5 - 20 = 50
= 77 - 20 = 50
= 57 \not= 50
Thus, the correct option is: (c)

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