Which two numbers should be interchanged to make the given equation correct?
18 × 3 ÷ 9 + 5 – 6 = 2

Correct option is C

Given: 18 × 3 ÷ 9 + 5 – 6 = 2
From the given options -
Bodmas table-
​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$​​
(a) 18 and 6 after interchanging the digit we get following equation-
6 × 3 ÷ 9 + 5 – 18 = 2
6 × 1/3 + 5 – 18 = 2
2 + 5 – 18 = 2
7 – 18 = 2
-11 ≠ 2
(b) 3 and 5 after interchanging the digit we get following equation-
18 × 5 ÷ 9 + 3 – 6 = 2
18 × 5/9 + 3 – 6 = 2
10 + 3 – 6 = 2
13 – 6 = 2
7 ≠ 2
(c) 2 and 3 after interchanging the digit we get following equation-
18 × 2 ÷ 9 + 5 – 6 = 3
18 × 2/9 + 5 – 6 = 3
4 + 5 – 6 = 3
9 – 6 = 3
3 = 3
Thus, the correct answer is (c) 2 and 3.