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    Which two numbers (not digits) should be interchanged to make the given equation correct? 21 × 8 – 18 + (64 ÷ 2) + 32 = 64
    Question

    Which two numbers (not digits) should be interchanged to make the given equation correct?
    21 × 8 – 18 + (64 ÷ 2) + 32 = 64

    A.

    8 and 18

    B.

    8 and 2

    C.

    18 and 32

    D.

    32 and 64

    Correct option is B

    Given: 
    21 × 8 – 18 + (64 ÷ 2) + 32 = 64
    Operation preference wiseSymbolBrackets[],,()Orders, of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline\textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & (power), √ (root) , of \\ \hline \text{Division}& ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline \end{array} ​​
    Let's put the options:
    A) 8 and 18
    New Expression: 
    21 × 18 – 8 + (64 ÷ 2) + 32 = 64
    21 × 18 – 8 + 32 + 32 = 64
    378 – 8 + 32 + 32 = 64
    378 – 8 + 32 + 32 = 64
    442 – 8 = 64 
    434 = 64 (Incorrect)
    B) 8 and 2
    New Expression: 
    21 × 2 – 18 + (64 ÷ 8) + 32 = 64
    21 × 2 – 18 + 8 + 32 = 64
    42 – 18 + 8 + 32 = 64
    82 – 18 = 64 
    64 = 64 (Correct)
    Thus, correct option is (b).


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