Which two numbers (not digits) should be interchanged to make the given equation correct?
​$$(√144÷4)^3+(6)^2-(28×2)+72+(32÷8)×3=52$$​​

Correct option is D

Given: $$(√144÷4)^3+(6)^2-(28×2)+72+(32÷8)×3=52$$​​
As per the option interchanging the 4 and 6 we get following equation-
​$$(√144÷6)^3+(4)^2-(28×2)+72+(32÷8)×3=52 \\(12÷6)^3+(4)^2-(28×2)+72+(4)×3=52 \\(2)^3+(4)^2-(28×2)+72+(4)×3=52 \\8+16-56+72+12=52 \\8+16-56+72+12=52 \\108 – 56 = 52 \\52 = 52$$​​
Correct answer is (d) 4 and 6