Which two numbers and signs should be interchanged to make the following equation correct?

​$$14 \times 3 \div 6-12+13=8$$​​

Given: 14 × 3 ÷ 6 − 12 + 13 = 8
Logic: BODMAS

​$$\begin{array}{|c|c|} \hline\textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & (power), √ (root) , of \\ \hline \text{Division}& ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}$$​​

Let's check all options:

Option (a): 14 and 12, × and ÷  (Incorrect)

After interchanging the number and signs,

Equation becomes: 12 ÷ 3 × 6 − 14 + 13 = 8

 12 ÷ 3 × 6 − 14 + 13 = 8

 4 × 6 − 14 + 13 = 8

 24 − 14 + 13 = 8

37 - 14 = 8

23 $$\ne$$ 8​
​Option (b): 12 and 13, + and -  (Correct)​
After interchanging the number and signs,

Equation becomes: 14 × 3 ÷ 6 + 13 − 12 = 8

14 × 3 ÷ 6 + 13 − 12 = 8

14 × $$\frac{3}{6}$$​ + 13 − 12 = 8

7 + 13 − 12 = 8

20 − 12 = 8

​Option (c): 6 and 12, × and -  (Incorrect)​

After interchanging the number and signs,

Equation becomes: 14 − 3 ÷ 12 × 6 + 13 = 8

 14 − 3 ÷ 12 × 6 + 13 = 8

 14 − 0.25 × 6 + 13 = 8

 14 −0.25 × 6 + 13 = 8

14 - 1.5 + 13 = 8

27 - 1.5 = 8

25.5 $$\ne$$ 8​
​Option (d): 12 and 14, × and -  (Incorrect)​

After interchanging the number and signs,

Equation becomes: 12 − 3 ÷ 6 × 14 + 13 = 8

12 − 3 ÷ 6 × 14 + 13 = 8

 12 − ​ × 14 + 13 = 8

12 −  7  + 13 = 8

25 - 7 = 8

Thus, the correct option is (b)  12 and 13, + and -

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