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Which one of the following is the standard deviation of the first 7 (1 to 7) natural numbers?
Question



Which one of the following is the standard deviation of the first 7 (1 to 7) natural numbers?

A.

4

B.

3

C.

2

D.

6

Correct option is C

Step-by-step Calculation:1. Given values: First 7 natural numbers: 1,2,3,4,5,6,7.2. Calculate the mean (xˉ):xˉ=xin=1+2+3+4+5+6+77=287=43. Calculate (xixˉ)2 for each value:(14)2=9,(24)2=4,(34)2=1,(44)2=0,(54)2=1,(64)2=4,(74)2=94. Sum of squared deviations:(xixˉ)2=9+4+1+0+1+4+9=285. Calculate variance:Variance=(xixˉ)2n=287=46. Calculate standard deviation:SD=Variance=4=2\textbf{Step-by-step Calculation:}1. \ \text{Given values: First 7 natural numbers: } 1, 2, 3, 4, 5, 6, 7. \\2. \ \text{Calculate the mean } (\bar{x}): \\\bar{x} = \frac{\sum x_i}{n} = \frac{1 + 2 + 3 + 4 + 5 + 6 + 7}{7} = \frac{28}{7} = 4 \\3. \ \text{Calculate } (x_i - \bar{x})^2 \text{ for each value:} \\(1 - 4)^2 = 9, \\(2 - 4)^2 = 4, \\(3 - 4)^2 = 1, \\(4 - 4)^2 = 0, \\(5 - 4)^2 = 1, \\(6 - 4)^2 = 4, \\(7 - 4)^2 = 9 \\4. \ \text{Sum of squared deviations:} \\\sum (x_i - \bar{x})^2 = 9 + 4 + 1 + 0 + 1 + 4 + 9 = 28 \\5. \ \text{Calculate variance:} \\\text{Variance} = \frac{\sum (x_i - \bar{x})^2}{n} = \frac{28}{7} = 4 \\6. \ \text{Calculate standard deviation:} \\SD = \sqrt{\text{Variance}} = \sqrt{4} = 2​​

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