Correct option is B
From Equation (3):x=20−y−2z(4)Substitute Equation (4) into (1) and (2)Substituting into Equation (1):3(20−y−2z)+y+5z=3060−3y−6z+y+5z=3060−2y−z=30=>2y+z=30(5)Substituting into Equation (2):2(20−y−2z)+2y+3z=4040−2y−4z+2y+3z=4040−z=40=>z=0(6)Substitute z=0 into Equation (5)2y+0=30=>y=15Substitute y=15,z=0 into Equation (4) to find xx=20−15−2(0)=5