Correct option is A
Given - # : VEC :: BNW : %

Option A:
#= XHA, % = ZKY
Check XHA → VEC
X → V = –2
H → E = –3
A → C = +2
and
BNW → ZKY
B → Z = –2
N → K = –3
W → Y = +2 - prefect matching BNW → XHA
Option B:
#= ZKY, % = FTS
ZKY → VEC
Z → V = –4
K → E = –6
Y → C = +4
and
BNW → FTS
B → F = +4
N → T = +6
W → S = –4 = Not matching
Option C:
# = FTS, % = XHA
Check FTS → VEC
F - 10 = V
T + 11 = E
S + 10 = C
and
BNW → XHA
B - 6 = X
N - 6 = H
W + 4 = A Not matching
Option D:
= DQU, % = XHA
DQU → VEC
D → V = - 8
Q → E = - 12
U → C = + 6,
Already seen BNW → XHA - Not matching
Final Answer:
#= XHA, % = ZKY
Final Correct Option: (A) #= XHA, % = ZKY