Correct option is C

Option (C):
# = SRA and % = QMY
So,
SRA : UWC :: OHW : QMY
Step 1: Check the pattern between SRA → UWC
Compare each letter in order:
From To Operation
S → U +2
R → W +5
A → C +2
Hence, the pattern followed is (+2, +5, +2) in the alphabetical order.
Step 2: Apply the same pattern to OHW
From +2 +5 +2
O → Q H → M W → Y
Result = QMY
Since the same (+2, +5, +2) logic is valid in both cases —
SRA → UWC and OHW → QMY —
the relationship is perfectly consistent.
The correct answer is: (c) # = SRA and % = QMY