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    Which of the following interchanges of signs would make the given equation correct? 3-6÷ 9 + 6 × 2 = 6
    Question

    Which of the following interchanges of signs would make the given equation correct?
    3-6÷ 9 + 6 × 2 = 6

    A.

    ÷ and ×

    B.

    + and ×

    C.

    ÷ and +

    D.

    – and ×

    Correct option is D

    Given :

    ​​3-6÷ 9 + 6 × 2 = 6

    Solution: 

    Interchange sign

    Option (a) :  ÷\div , ×\times 

    36×9+62=63 - 6 \times 9 + \frac{6}{2} = 6 

    354+3=63 - 54 + 3 = 6 

    51+3=47-51 + 3 = -47 (False)

    Option (b): +, ×\times 

    369×6+2=63 - \frac{6}{9} \times 6 + 2 = 6 

    34+2=63 - 4 + 2 = 6 


    1+2=6-1 + 2 = 6 

    1=61 = 6 (False)

    Option (c):  ÷\div , +

    36+96×2=63 - 6 + \frac{9}{6} \times 2 = 6 

    36+2=63 - 6 + 2 = 6 

    3+2=6-3 + 2 = 6  

    1=6-1 = 6 (False)

    Option (d): -, ×\times

    3×69+62=63 \times \frac{6}{9} + 6 - 2 = 6 

    2+62=62 + 6 - 2 = 6  

    6=66 = 6 ( It is true).

    Correct Option : (d)

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