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Which of the following interchanges of signs would make the given equation correct? 3-6÷ 9 + 6 × 2 = 6
Question

Which of the following interchanges of signs would make the given equation correct?
3-6÷ 9 + 6 × 2 = 6

A.

÷ and ×

B.

+ and ×

C.

÷ and +

D.

– and ×

Correct option is D

Given :

​​3-6÷ 9 + 6 × 2 = 6

Solution: 

Interchange sign

Option (a) :  ÷\div , ×\times 

36×9+62=63 - 6 \times 9 + \frac{6}{2} = 6 

354+3=63 - 54 + 3 = 6 

51+3=47-51 + 3 = -47 (False)

Option (b): +, ×\times 

369×6+2=63 - \frac{6}{9} \times 6 + 2 = 6 

34+2=63 - 4 + 2 = 6 


1+2=6-1 + 2 = 6 

1=61 = 6 (False)

Option (c):  ÷\div , +

36+96×2=63 - 6 + \frac{9}{6} \times 2 = 6 

36+2=63 - 6 + 2 = 6 

3+2=6-3 + 2 = 6  

1=6-1 = 6 (False)

Option (d): -, ×\times

3×69+62=63 \times \frac{6}{9} + 6 - 2 = 6 

2+62=62 + 6 - 2 = 6  

6=66 = 6 ( It is true).

Correct Option : (d)

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