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    Which of the following equations represents the graph shown?
    Question

    Which of the following equations represents the graph shown?

    A.

    log y = (log x) - 1

    B.

    log y = (log x)/2 - 1

    C.

    log y = (log x) - log(1)

    D.

    log y = (log x)/2 + 1

    Correct option is B

    Given:
    The graph is a straight line between log y (Y-axis) and log x (X-axis).
    From the graph:
    When log x = 0, log y = -1
    When log x = 2, log y = 0
    Using the line equation:
    log y = m * log x + c

    Calculate slope (m):

    m=ΔY/ΔX=(0(1))/(20)=1/2m = ΔY / ΔX = (0 - (-1)) / (2 - 0) = 1 / 2

    Now, use point (0, -1) to find c:

    logy=(1/2)logx+c1 =(1/2)0+cc=1log y = (1/2) * log x + c-1 \\\ \\= (1/2)*0 + c → c = -1

    logy=(1/2)logx1log y = (1/2) * log x - 1

    Final Answer: (b) log y = (log x)/2 - 1
    Important Key Points:
    The graph shows a log-log straight line, representing a power function.
    Slope is 1/2, derived from change in log y over change in log x.
    Y-intercept is -1, confirming the constant in the equation.​

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