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When 1985,6814 and 3741 are divided by the largest number x, the remainder is same in each case. What is the sum of the digits of x?
Question

When 1985,6814 and 3741 are divided by the largest number x, the remainder is same in each case. What is the sum of the digits of x?

A.

19

B.

11

C.

16

D.

13

Correct option is C

Solution:

First, find the differences between the given numbers:

6814 - 1985 = 4829

6814 - 3741 = 3073

3741 - 1985 = 1756

The largest number x that divides each of these differences is the greatest common divisor (GCD) of 4829, 3073, and 1756.

Using the Euclidean algorithm, we find:

GCD(4829, 3073) = 439

GCD(439, 1756) = 439

Therefore, the largest number x is 439.

The sum of the digits of x is:

Sum of digits of 439 = 4 + 3 + 9 = 16

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