What will be the total active power consumed by a 3-phase, delta-connected system, which is supplied with a line voltage of 230 V, when the value of the phase current is 15 A and the current lags the voltage by 30°?

Correct option is C

$$\text{Given:} \\[4pt]\bullet \; \text{Type of connection: Delta} \\[4pt]\bullet \; \text{Line voltage } V_L = 230\,\text{V} \\[4pt]\bullet \; \text{Phase current } I_p = 15\,\text{A} \\[4pt]\bullet \; \text{Power factor angle } \phi = 30^\circ \\[10pt]\text{For a delta-connected system, active power is given by:} \\[4pt]P = 3 \times V_p \times I_p \times \cos \phi \\[8pt]\text{(Since in delta, } V_p = V_L \text{)} \\[6pt]P = 3 \times 230 \times 15 \times \cos(30^\circ) \\[6pt]P = 3 \times 230 \times 15 \times 0.866 \\[6pt]P = 8.963\,\text{kW}$$​​