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What will be the output of the code snippet?
Question



What will be the output of the code snippet?

A.

10

B.

15

C.

5

D.

Compilation Error

E.

None of the above

Correct option is B


1. Variable Initialization: x is declared and initialized to 10.
2. Pointer Initialization: a is declared as a pointer to an integer and initialized to the address of x. Now, *a points to x.
3. Dereferencing and Modification: *a = *a + 5; This statement adds 5 to the value pointed to by a, which is x. So: x = x + 5 = 15.
4. Output: printf("%d\n", *a); prints the value of x, which is now 15.
Key Points:
1. Dereferencing a pointer (*a) accesses the value stored at the memory address it points to.
2. Modifying *a directly updates the value of x since a points to the memory location of x.
Knowledge Booster:
· Pointer Basics: A pointer stores the address of a variable, and dereferencing a pointer (*) allows access to the value stored at that address.
· Use Case: Pointers are crucial for dynamic memory management, function arguments (pass by reference), and data structures like linked lists.

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