Correct option is BGiven: log10(0.00001)log₁₀(0.00001)log10(0.00001) Concept Used: log1010nlog₁₀10^nlog1010n = nlog1010nlog₁₀10nlog1010 = n×1n\times 1 n×1 = n log1010=1log10^{10} = 1log1010=1 Solution: log10(0.00001)log₁₀(0.00001)log10(0.00001) = log10(10−5)log₁₀(10^{-5})log10(10−5) = −5log1010-5 log₁₀10−5log1010 = -5