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What is the value of [41×{36×4÷(96×2÷24)}]\left[ 41 \times \left\{ 36 \times 4 \div \left( 96 \times 2 \div 24 \right) \right\} \right][41×{36×4÷(96×2
Question

What is the value of [41×{36×4÷(96×2÷24)}]\left[ 41 \times \left\{ 36 \times 4 \div \left( 96 \times 2 \div 24 \right) \right\} \right]​​

A.

656

B.

697

C.

738

D.

779

Correct option is C

Given:
[41×{36×4÷(96×2÷24)}]\left[ 41 \times \left\{ 36 \times 4 \div \left( 96 \times 2 \div 24 \right) \right\} \right]​​
Concept Used:

Priority wise Operation

Symbol/चिह्न

B-Bracket/कोष्ठक

(), {}, []

O-Of/का

Of/का

D-Division/विभाजन

/,÷

M-Multiplication/गुणा

×, *

A-Addition/जोड़

+

S-Subtraction/घटाव

-

Solution:
[41×{36×4÷(96×2÷24)}][41×{36×4÷(96×112)}][41×{36×4÷8}][41×{36×12}]41×18=738\left[ 41 \times \left\{ 36 \times 4 \div \left( 96 \times 2 \div 24 \right) \right\} \right]\\\left[ 41 \times \left\{ 36 \times 4 \div \left( 96 \times\frac{1}{12} \right) \right\} \right]\\\left[ 41 \times \left\{ 36 \times 4 \div 8 \right\} \right]\\\left[ 41 \times \left\{ 36 \times \frac{1}{2}\right\} \right]\\41 \times 18 = 738​​

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