What is the value of  

​$$\frac{[\frac{1}{5}÷\frac{1}{5}×\frac{1}{5}]×\frac{1}{5}}{[\frac{1}{9}+\frac{1}{9}×\frac{1}{9}]×\frac{1}{10}} + (1-\frac{6}{25}) = ?\\$$​​

Correct option is D

Concept  Used:

$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$

 Solution: 

$$\frac{[\frac{1}{5}÷\frac{1}{5}×\frac{1}{5}]×\frac{1}{5}}{[\frac{1}{9}+\frac{1}{9}×\frac{1}{9}]×\frac{1}{10}} + (1-\frac{6}{25}) = ?\\\ \\ \frac{[\frac{1}{5}\times 5×\frac{1}{5}]×\frac{1}{5}}{[\frac{1}{9}+\frac{1}{81}]×\frac{1}{10}} + (\frac{19}{25}) = ?\\\ \\ \frac{\frac{1}{25}}{[\frac{10}{81}]×\frac{1}{10}} + (\frac{19}{25}) = ?\\\ \\ \frac{81}{25} + (\frac{19}{25}) = ?\\\ \\ \frac{81+19}{25}= ?\\\ \\ \frac{100}{25}= 4$$​