Given:
We are asked to find the smallest possible number which when divided by 7, 9, and 11 leaves a remainder of 2 in each case.
Formula Used:
LCM (Least Common Multiple) is used to find the smallest number divisible by multiple numbers.
If a number leaves the same remainder 'r' when divided by a, b, c, then:
Required number = LCM(a, b, c) + r
Solution:
Since 7, 9, and 11 are co-prime (no common factors),
LCM = 7 × 9 × 11 = 693
Required number = 693 + 2 = 695
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100 Questions
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60 Mins English English25 Questions50 Marks15 Mins English English100 Questions200 Marks60 Mins EnglishFind the smallest number which when increased by 20 is completely divisible by 12, 20, 15, 18 and 24.
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