Given:
We are asked to find the smallest possible number which when divided by 7, 9, and 11 leaves a remainder of 2 in each case.
Formula Used:
LCM (Least Common Multiple) is used to find the smallest number divisible by multiple numbers.
If a number leaves the same remainder 'r' when divided by a, b, c, then:
Required number = LCM(a, b, c) + r
Solution:
Since 7, 9, and 11 are co-prime (no common factors),
LCM = 7 × 9 × 11 = 693
Required number = 693 + 2 = 695
English
80 Questions
160 Marks
60 Mins English English20 Questions40 Marks12 Mins English English80 Questions160 Marks60 Mins EnglishFind the Highest Common Factor (HCF) of 372, 732 and 2196.
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