What is the smallest perfect square which is divisible by both 12 and 5?

Correct option is C

Given:
The number must be divisible by both 12 and 5, and it must be a perfect square.
Formula Used:
A perfect square must have even powers of all its prime factors.
Solution:
Prime factorization of 12 = $$2^2$$​ × 3
Prime factorization of 5 = 5
​$$LCM(12, 5) = 2^2 × 3 × 5 = 60.$$​​
To make the LCM a perfect square, all prime factors must have even powers:
Increase the power of 3 from 1 to 2 and the power of 5 from 1 to 2.
The smallest perfect square divisible by both 12 and 5 is:
​$$2^2 \times 3^2 \times 5^2 = 4 \times 9 \times 25 = 900$$​​